剑指 Offer 15. 二进制中 1 的个数
easy
编写一个函数,输入是一个无符号整数(以二进制串的形式),返回其二进制表达式中数字位数为 ‘1’ 的个数(也被称为 汉明重量).)。
示例 1:
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| 输入:n = 11 (控制台输入 00000000000000000000000000001011)
输出:3
解释:输入的二进制串 00000000000000000000000000001011 中,共有三位为 '1'
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位运算
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| func hammingWeight(num uint32) (count int) {
for num > 0 {
if num&1 == 1 {
count++
}
num = num >> 1
}
return
}
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| func hammingWeight(num uint32) (ones int) {
for i := 0; i < 32; i++ {
if 1<<i&num > 0 {
ones++
}
}
return
}
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位运算优化
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| func hammingWeight(num uint32) (ones int) {
for ; num > 0; num &= num - 1 {
ones++
}
return
}
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